Calc questions that need answers

calculus test / quiz prep and need the explanation and answer to help me learn.

I have a pdf that has 11 calc questions and i need a step by step answer to all questions.
Requirements: Detailed steps for the answer.
1.2.3.4.5.6.Student: _____________________Date: _____________________Instructor: TAOUFIK MEKLACHICourse: Math 140 ClassTestAssignment: Practice quiz 7The given point is on the curve. Find the lines that are a. tangent and b. normal to the curve at the given point. , ( , )x+xy−y22=−112a. Give the equation of the tangent line to the curve at the given point.y=b. Give the equation of the normal line to the curve at the given point.y=Verify that the given point is on the curve. Find the lines that are a. tangent and b. normal to the curve at the given point. , 2xy+πsiny=13π2,7π2Choose the correct verification below.A.2(2)+πsin7π27π2?= 13π13π=13πB.2(2)+πsin(2)7π2?= 13π13π=13πa. Write the equation of the tangent line to the curve at .2,7π2y= (Type an exact answer, using as needed.)πb. Write the equation of the normal line to the curve at .2,7π2y= (Type an exact answer, using as needed.)πFind the derivative of y with respect to x.y=8ln(cosx)dydx=Find the derivative of y with respect to .θy=ln(θ+5)+eθ dydθ=Find the derivative of y with respect to x.y=lnx7dydx=Find the derivative of y with respect to t.y=t()ln10t2dydt=
7.8.9.10.11.Given the function f and point a below, complete parts (a) (c).– , , af(x)=5x2x≥0=6a. Find . f(x)−1f(x)−1=b. Graph f and together. Choose the correct graph below.f−1A.0808xyB.0808xyC.0808xyc. Evaluate at and at to show that .dfdxx=adf−1dxx=f(a)=df−1dx x=f(a)1(df/dx)x=adfdxx=6=df−1dxx=f(6)=Use a reference triangle in an appropriate quadrant to find the given angle.tan−133tan−133= (Type an exact answer, using as needed. Use integers or fractions for any numbers in the expression.)πUse a reference triangle to find the given angle.sin−112sin−112= (Type an exact answer in terms of .)πFind the derivative of y with respect to t.y=cot−16tdydt=Find the derivative of y with respect to x.y=lntan−19x3dydx=
1.x+4323−x+341142.A. 2(2)+πsin7π27π2?= 13π13π=13π−x+7π7π4x+47π49π2−1614π3.−8tan x4.+e1θ+5θ5.7×6.2ln10t+(ln10t)27.×151/21/2A. 0808xy601608.π69.π610.−36t(1+6t)
11.27x2tan−19×31+81×6

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